tag:blogger.com,1999:blog-831309579862171927.post4712065980452912312..comments2024-03-28T00:13:41.522-07:00Comments on Keith Hack: Current MeasurementKeith Wakehamhttp://www.blogger.com/profile/04750593468902337123noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-831309579862171927.post-83313657343664944472023-10-14T04:30:37.547-07:002023-10-14T04:30:37.547-07:00Thhank you for sharingThhank you for sharingLove Maeganhttps://lovemaegan.tumblr.com/noreply@blogger.comtag:blogger.com,1999:blog-831309579862171927.post-760188897485142982013-05-16T02:11:14.149-07:002013-05-16T02:11:14.149-07:00Actually I completely missed pages 34 etc.
I'...Actually I completely missed pages 34 etc.<br /><br />I'll try to do a theoretical calc and see what I come up with.Anonymoushttps://www.blogger.com/profile/05194096660242924230noreply@blogger.comtag:blogger.com,1999:blog-831309579862171927.post-21006172442158296832013-05-16T02:09:43.340-07:002013-05-16T02:09:43.340-07:00Just so I understand correctly.
Currently the nRF5...Just so I understand correctly.<br />Currently the nRF51x is drawing 1.8mA constantly?<br /><br />Because from page 32 of the nRF51 I can't particular see how it can be drawing this much. Everything quoted is 'typical', but it only adds up to about 0.9mA which is 50% less than your measured current.Anonymoushttps://www.blogger.com/profile/05194096660242924230noreply@blogger.com